daveylibra
New member
- Joined
- Nov 9, 2017
- Messages
- 16
Hi, I have searched and cannot find a similar question to this that has been answered...
Q. With a fair coin, my opponent flips 50 times, with fair odds, ie I double my bet on a win.
The average outcome is 25 wins, 25 losses.
However, if I make the assumption that I will win at least 15 times, how do I proportion my bets
to be ahead at the 15th win, whilst minimising bets?
Further, write an equation to illustrate this with e= expected wins, n= total flips.
I know e=15, n=50.
I think if c=expected wins at any point in the series, bet=1+(losses/c) should be right, but
it does not take into account n.
I have asked an engineering graduate who is stuck. Any help, please?
Q. With a fair coin, my opponent flips 50 times, with fair odds, ie I double my bet on a win.
The average outcome is 25 wins, 25 losses.
However, if I make the assumption that I will win at least 15 times, how do I proportion my bets
to be ahead at the 15th win, whilst minimising bets?
Further, write an equation to illustrate this with e= expected wins, n= total flips.
I know e=15, n=50.
I think if c=expected wins at any point in the series, bet=1+(losses/c) should be right, but
it does not take into account n.
I have asked an engineering graduate who is stuck. Any help, please?