student127
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- Joined
- Nov 18, 2017
- Messages
- 2
Hello, I need to find the surface area of a curved trapeze that is limited by the following functions; x = y^2 - 8 and -2y + 1. For an example like y=4X, y=0, x= 1 it is easy to do and would just be calculating integral of 4x and it's defined integral within bounds 0-1 and then using Newton-Leibinz formula. But in this example the functions are being defined against x and this confuses me. https://gyazo.com/6285709adfb42ddd9dfb2193c92dc901 is the kind of graphic it should be.Using symbolabs integral applications I got this: https://www.symbolab.com/solver/int...\left(y\right)=y^{2}-8, f\left(y\right)=-2y+1 But the graph isn't the same there, and also the bounds aren't the same: Bounds should be from -8 to 9.325 right?
How must I go about finding the surface area of this type?
What must I integrate and calculate the definite integral of?
Is the symbolab example correct and I just don't understand why?
Any help appreciated,
Best regards
How must I go about finding the surface area of this type?
What must I integrate and calculate the definite integral of?
Is the symbolab example correct and I just don't understand why?
Any help appreciated,
Best regards