yo. whats the missing math here.......i cant seem to figure it out tonight.

[tex]f(f^{-1}(x)) = \frac{1}{3(\frac{1-2x}{3x})+2}=...=x[/tex]

right? the composition of a function and its inverse is x?

i just get [tex]\frac{1-2x}{x}+2 = \frac{1}{x}[/tex]

Edit: nevermind i got it....writing it down on here seemed to help for some reason.

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