Reallybadatmath
New member
- Joined
- Nov 24, 2017
- Messages
- 2
Hello I'm having trouble with a problem that goes like this:
You have 21 plastic boxes. 17 are white, 4 are red. All the red boxes are empty. 14 of the white boxes are empty. 3 white boxes have prices hidden inside of them. So, to sum it up:4 empty red boxes;17 empty white boxes; 3 prize filled white boxes.
You then pick a box at random; and you get a white box. What is the probability that you won a price?
I think it might be 4/17; but I dont know if this is a Monty-Hall type situation where the seemingly obvious answer is wrong.
You have 21 plastic boxes. 17 are white, 4 are red. All the red boxes are empty. 14 of the white boxes are empty. 3 white boxes have prices hidden inside of them. So, to sum it up:4 empty red boxes;17 empty white boxes; 3 prize filled white boxes.
You then pick a box at random; and you get a white box. What is the probability that you won a price?
I think it might be 4/17; but I dont know if this is a Monty-Hall type situation where the seemingly obvious answer is wrong.