# Thread: Limit, x=>+infinity, ln(3^x - x) [ ln(x^4 + 1) - 2 ln(x^2 - x) ]

1. ## Limit, x=>+infinity, ln(3^x - x) [ ln(x^4 + 1) - 2 ln(x^2 - x) ]

Help for:

. . . . .$\displaystyle \lim_{x \rightarrow \infty}\, \ln\left(3^x\, -\, x\right)\, \big[\ln\left(x^4\, +\, 1\right)\, -\, 2\, \ln\left(x^2\, -\, x\right)\big]$

2. Originally Posted by Noismaker
Help for:

. . . . .$\displaystyle \lim_{x \rightarrow \infty}\, \ln\left(3^x\, -\, x\right)\, \big[\ln\left(x^4\, +\, 1\right)\, -\, 2\, \ln\left(x^2\, -\, x\right)\big]$
Have you considered rules of Logarithms? Show us where that gets you.

3. Originally Posted by Noismaker
Help for:

. . . . .$\displaystyle \lim_{x \rightarrow \infty}\, \ln\left(3^x\, -\, x\right)\, \big[\ln\left(x^4\, +\, 1\right)\, -\, 2\, \ln\left(x^2\, -\, x\right)\big]$
What have you covered recently in class? (That is, what tools are you probably expected to use for this exercise?) I mean, yes, we can find the limit by other means, but you can't likely expect your instructor to "trust you for it"; ya gotta show yer work!

When you reply, please include a clear listing of your thoughts and efforts so far. Thank you!

#### Posting Permissions

• You may not post new threads
• You may not post replies
• You may not post attachments
• You may not edit your posts
•