Thread: How to reduce original 70" X 32" (L X H) rectangle, given new L is 50" ?

1. How to reduce original 70" X 32" (L X H) rectangle, given new L is 50" ?

The original rectangle is 70" X 32" (L X H)

If the length were reduced to 50", what would the height be?

Thank you Math Savants.

2. Originally Posted by sigbonner
The original rectangle is 70" X 32" (L X H)

If the length were reduced to 50", what would the height be?

Thank you Math Savants.
Use ratio!

Please share your work with us ...even if you know it is wrong.

If you are stuck at the beginning tell us and we'll start with the definitions.

http://www.freemathhelp.com/forum/announcement.php?f=33

3. 70 : 32
50 : ?

4. Originally Posted by sigbonner
The original rectangle is 70" X 32" (L X H)

If the length were reduced to 50", what would the height be?
Are you supposed to keep the aspect ratio (so that the height is to be reduced in such a manner as to keep the picture the same, without stretching or squishing)? If so, use ratios, as the first reply suggested. Use them to set up a proportion, using the info the second reply provided:

Originally Posted by Denis
70 : 32
50 : ?
Originally Posted by JorgeReiki
I Dont...
"You don't"... what? You don't know what ratios are? You don't know how to solve proportions? The picture isn't supposed to retain its aspect ratio, so the earlier hints don't apply? Or something else?

5. Thank you for the direction to your ratios page.

70:32
50:X

70x = 1600

70 = 1600/x

1600 \ 70X = 22.85

6. Originally Posted by sigbonner
Yes -- but your decimal approximation is not properly rounded.

The exact answer is 160/7 (that's 22 6/7 inches).

70x = 1600

70 = 1600/x

1600 \ 70X = 22.85
70x = 1600 is good.

Next, one step will solve for x: divide each side by 70

x = 1600/70

PS: Don't switch between symbols x and X. Use one or use the other, not both.

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