Hi everyone. I am struggling with solving the following equation.
11^a=9 (mod 23)
I know that we have to use logarithms here, but do not know how to implement it... Could someone explain me how to solve it. Thank you in advance.
Hi everyone. I am struggling with solving the following equation.
11^a=9 (mod 23)
I know that we have to use logarithms here, but do not know how to implement it... Could someone explain me how to solve it. Thank you in advance.
Geesshhhh...did you know that 9 mod 23 = 9?
11^a = 9
a = LOG(9) / LOG(11)
Take over, Rover
What is 30 mod 23?
I'm just an imagination of your figment !
Bro, I know it, This equation has the answer, and it is 6. I want to know how to solve it, not just estimating.
Are you studying something like what they discuss here? Also, are you working with "discrete" logs?
Thank you!
Here is a discussion of this sort of problem, going into some depth for both a small problem like yours, and a large one (which would easily take the place of a final exam).
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