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Thread: What does f(u)(t-u) mean in this convolution equation?

  1. #1

    What does f(u)(t-u) mean in this convolution equation?

    I don't understand what f(u)(t-u) means in the following maths problem. Is it somehow a function of a function or a function multiplied by (t-u)? Or something else? The question is:

    Please solve the following convolution equation:


    ∫ f(u)(t-u) cos(2(t-u)) du = ∫ sin(2u) sin(2(t-u)) du

    (Both integrals go from 0 to t)
    Last edited by Sofia12345; 01-07-2018 at 12:16 PM.

  2. #2
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    Quote Originally Posted by Sofia12345 View Post
    I don't understand what f(u)(t-u) means in the following maths problem. Is it somehow a function of a function or a function multiplied by (t-u)? Or something else? The question is:

    Please solve the following convolution equation:


    ∫ f(u)(t-u) cos(2(t-u)) du = ∫ sin(2u) sin(2(t-u)) du

    (Both integrals go from 0 to t)
    There is no strange notation being used here; it just means f(u) times (t-u), as one would expect.

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