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Thread: Inverse laplace transform, formula help please: L−1[e(-2πs-2s)/(s2-4)]

  1. #1

    Inverse laplace transform, formula help please: L−1[e(-2πs-2s)/(s2-4)]

    I have to find y, but i don't have a formula to solve that one, any idea?
    L−1[e(-2πs-2s)/(s2-4)]

  2. #2
    Elite Member
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    Can you do [tex]\dfrac{1}{s^{2}-4}[/tex]?

    Can you do [tex]\dfrac{e^{-s}}{s^{2}-4}[/tex]?

    Can you do [tex]\dfrac{e^{-(s+2)}}{s^{2}-4}[/tex]?

    Can you do [tex]\dfrac{e^{-(s+\pi)}}{s^{2}-4}[/tex]?

    Show your work. Let's see where it leads.
    "Unique Answers Don't Care How You Find Them." - Many may have said it, but I hear it most from me.

  3. #3

    unsolved

    for the firs question it is sin2t
    second , should i treat e^-s as a constant?
    i saw too a formula where F(s)=e-cs/s and than f(t)=uc(t)=u(t-c) but it still doesn't solve my problem

  4. #4
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    Quote Originally Posted by Justinetea View Post
    for the firs question it is sin2t
    second , should i treat e^-s as a constant? ............. No... s is the variable of integration. Any function of 's' cannot be treated as constant.
    i saw too a formula where F(s)=e-cs/s and than f(t)=uc(t)=u(t-c) but it still doesn't solve my problem
    .
    ... mathematics is only the art of saying the same thing in different words - B. Russell

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