4 radio locators with different constructions. probability of finding and object with the help of the first is 0.84, second – 0.90, third – 0.80 and forth – 0.95.
A viewer turns on one radio locator. What is the probability of finding an object ?
I'm guessing that this is the right answer(all of the probabilities added and then divided by 4) -> (0.84 + 0.90 + 0.80 + 0.95) / 4 = 3.49 / 4 = 0.87 ? Is that correct ?
But then I am asked the question - After turning on one of the radio locators an object is registered. what is the probability of this being the second radio locator ?
I know the formula for this is P(A|B) = P(AB) / P(B). In this case B should be the condition being met - the radio locator found an object. I don't know how to multiply A and B ?
Any idea or guidance ?
A viewer turns on one radio locator. What is the probability of finding an object ?
I'm guessing that this is the right answer(all of the probabilities added and then divided by 4) -> (0.84 + 0.90 + 0.80 + 0.95) / 4 = 3.49 / 4 = 0.87 ? Is that correct ?
But then I am asked the question - After turning on one of the radio locators an object is registered. what is the probability of this being the second radio locator ?
I know the formula for this is P(A|B) = P(AB) / P(B). In this case B should be the condition being met - the radio locator found an object. I don't know how to multiply A and B ?
Any idea or guidance ?