# Thread: How do I isolate for x within this equation? 2^x + 3 · 2^x = a^(2x)

1. ## How do I isolate for x within this equation? 2^x + 3 · 2^x = a^(2x)

2x + 3 · 2x = a2x

Also, I was given a question hint that I should divide both sides by 2x
but I'm not sure how to proceed onwards from that step.

Any help would be appreciated, thank you

2. Originally Posted by ToasterWoman101
2x + 3 · 2x = a2x

Also, I was given a question hint that I should divide both sides by 2x but I'm not sure how to proceed onwards from that step.
Please show us what you got, after dividing each side by 2^x and simplifying.

The next step would be taking the natural logarithm of each side.

3. Just as a note to other helpers here, this exact problem was also posted on the Askmath subreddit by someone with a very similar username (quite possibly the same person?). There, the OP has received several good hints as to how to start this problem.

4. Originally Posted by ksdhart2
Just as a note to other helpers here, this exact problem was also posted on the Askmath subreddit by someone with a very similar username (quite possibly the same person?). There, the OP has received several good hints as to how to start this problem.
The poster was also given the complete worked solution at the other location. I doubt we'll be hearing more on this here.