allegansveritatem
Full Member
- Joined
- Jan 10, 2018
- Messages
- 962
At 9:45 a bus left Point Reyes, CA, going north at 40 mph. 2 hours later, a second bus left Point Reyes going south at 35 mph. At what time will the buses be 230 miles apart?
I have set this up thus: first I divided 35 by 40 (.875), and devised this equation: 35t + 40(t-.875)=230 with the solution being:3.8 hours. So, at 9:45 plus 3 hours and 48 minutes or at 1:33 the buses will be 230 miles apart. Does this look right? Is this how to solve this problem? If so, why do we need to know that one bus left 2 hours before the other?
Something tells me I am overlooking something.
I have set this up thus: first I divided 35 by 40 (.875), and devised this equation: 35t + 40(t-.875)=230 with the solution being:3.8 hours. So, at 9:45 plus 3 hours and 48 minutes or at 1:33 the buses will be 230 miles apart. Does this look right? Is this how to solve this problem? If so, why do we need to know that one bus left 2 hours before the other?
Something tells me I am overlooking something.