Results 1 to 3 of 3

Thread: Adding and Dividing Piecewise Functions and their Domains?

  1. #1
    New Member
    Join Date
    Jan 2018
    Posts
    3

    Adding and Dividing Piecewise Functions and their Domains?

    IMG_4971.jpg
    We have these two graphs, and these two functions:
    A) (F+G)(x)
    and
    B) (F/G)(x).

    And the question is asking what the domains of these two functions are. I am having a lot of trouble understanding how to get to the proper answers. If anybody could explain this question I would be very grateful.

    Answers:

    A) (-∞, -1]u(1,2]u(3,∞)
    and
    B) (-∞,-4)u(-4,-1]u(1,2]u(3,∞)

  2. #2
    Elite Member
    Join Date
    Apr 2005
    Location
    USA
    Posts
    9,393
    Some general guidelines:

    1) If something isn't in BOTH functions, it cannot be in the SUM.
    2) Division offers an additional complication. If your denominator is zero (0), at any point, you'll have to think harder about that point.
    "Unique Answers Don't Care How You Find Them." - Many may have said it, but I hear it most from me.

  3. #3
    Elite Member mmm4444bot's Avatar
    Join Date
    Oct 2005
    Location
    Seattle
    Posts
    9,393
    If I were doing this exercise, I would begin by focusing on the endpoints of the lines shown, in the graphs of piecewise functions F(x) and G(x).

    I would label their coordinates. For each of these values of x, I would then calculate F+G.

    Next, I would carefully plot the F+G points calculated above, using graph paper. This would give me a visual aid to look at, going forward to consider what's happening at other values of x. And that, in turn, would help me to see where F+G exists (i.e., for which values of x it exists) and where it doesn't.
    "English is the most ambiguous language in the world." ~ Yours Truly, 1969

Tags for this Thread

Bookmarks

Posting Permissions

  • You may not post new threads
  • You may not post replies
  • You may not post attachments
  • You may not edit your posts
  •