Seed5813
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- Joined
- Jan 29, 2018
- Messages
- 24
1. LarCalcET6 7.1.069.
Find b such that the line y = b divides the region bounded by the graphs of y = 25 - x2 and y = 0 into two regions of equal area.
I got:
. . . . .\(\displaystyle \displaystyle \int_0^5\, (25\, -\, x^2)\, dx\, =\, \dfrac{250}{3}\)
Then tried to find:
. . . . .\(\displaystyle \displaystyle \int_0^b\, (25\, -\, x^2)\, dx\, =\, \dfrac{125}{3}\)
But I get stuck when I try to evaluate it:
. . . . .\(\displaystyle \displaystyle 3\int_0^b\, (25\, -\, x^2)\, =\, 125\)
. . . . .\(\displaystyle \displaystyle 3\left[\, 25x\, -\, \frac{1}{3}x^3\right]_0^b\, =\, 125\)
. . . . .\(\displaystyle \displaystyle 75b\, -\, b^3\, =\, 125\)
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Find b such that the line y = b divides the region bounded by the graphs of y = 25 - x2 and y = 0 into two regions of equal area.
I got:
. . . . .\(\displaystyle \displaystyle \int_0^5\, (25\, -\, x^2)\, dx\, =\, \dfrac{250}{3}\)
Then tried to find:
. . . . .\(\displaystyle \displaystyle \int_0^b\, (25\, -\, x^2)\, dx\, =\, \dfrac{125}{3}\)
But I get stuck when I try to evaluate it:
. . . . .\(\displaystyle \displaystyle 3\int_0^b\, (25\, -\, x^2)\, =\, 125\)
. . . . .\(\displaystyle \displaystyle 3\left[\, 25x\, -\, \frac{1}{3}x^3\right]_0^b\, =\, 125\)
. . . . .\(\displaystyle \displaystyle 75b\, -\, b^3\, =\, 125\)
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