7equestrian7
New member
- Joined
- Feb 2, 2018
- Messages
- 4
Hi, I'm in AP Calculus BC, but I'm on medical leave without a teacher or tutor, so I'm stuck on a couple problems. Please show me how to do these, it would be greatly appreciated!
1. The motion of a particle is given by x=-2t2 and y=t3-3t+9, t>0. Find the coordinates of the particle when its instantaneous direction of motion is horizontal.
I know the answer is (-2, 7) but I'm not quite sure how to get there. I have started by finding dx/dt= -4t and dx/dy= 3t2-3, but unsure of where to go from here.
2. The motion of a particle is given by x=lntand y=t2-4t. Find the coordinates of the particle when its instantaneous direction of motion is horizontal.
I know the answer is (ln2, -4) but I'm not quite sure how to get there. I have started by finding dx/dt= 1/t and dy/dt= 2t-4, but unsure of where to go from here.
1. The motion of a particle is given by x=-2t2 and y=t3-3t+9, t>0. Find the coordinates of the particle when its instantaneous direction of motion is horizontal.
I know the answer is (-2, 7) but I'm not quite sure how to get there. I have started by finding dx/dt= -4t and dx/dy= 3t2-3, but unsure of where to go from here.
2. The motion of a particle is given by x=lntand y=t2-4t. Find the coordinates of the particle when its instantaneous direction of motion is horizontal.
I know the answer is (ln2, -4) but I'm not quite sure how to get there. I have started by finding dx/dt= 1/t and dy/dt= 2t-4, but unsure of where to go from here.