What is the rate of change of the volume of a ball

V=(4/3)* π * r^3

with respect to the radius when the radius is equals=4?

The volume changes at a rate of?

(Type an exact answer, using pi as needed.)

So i started with

r = 4, insert into the equation.

V=(4/3)*pi*r^3

V= (4/3)*pi*(4)^3

V= 4/3*pi* 64

Then, slope of the curve at point (r,V)

lim h->0 f(r+h)-f(r)/h

=lim h->0 (f(4+h) - (4/3*pi*64))/h

=lim h->0 ((4/3*pi (4+h)^3) -(4/3*pi*64))/h

am I on the right track?

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