
New Member
finally got it!
I tried to post earlier but apparently did not press the correct button.
I did finally notice that e^{2x}(K+P_{0}(e^{2x }1))would equal 0+P_{0}*1 0.
This would equal KP_{0 }in the numerator and P_{0 }in denominator.
So the answer is K
Thanks for everyone's help. I will check into the concepts of the other posts as well.
What is the technique of multiplying that way called? It is almost like rationalizing the numerator?
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