DavidMatthews
New member
- Joined
- Feb 17, 2018
- Messages
- 4
Okay, from my understanding, the question goes like this. You have a normal 6 sided die and a limited number of throws, x. You've already rolled y unique numbers, you have r throws left and you need to get z unique numbers. You don't know how may throws it took to get the y unique numbers you already have but you have to find the probability that the next throw is another unique number as in, not one of the y values you've obtained.
I'm terrible at probability and my idea of solving this was (6-y)/6, as in (number of values left)/total space. This failed on a few test cases and I'm pretty sure z and x have to play a part in the equation somehow.
I'm not asking for exact answers but directions, I really want to understand this and why my answer is so awe-full, the other variables add restrictions, how do I arrive at an equation that shows this? Thank you so much. Some links to similar questions would also be greatly appreciated!
I'm terrible at probability and my idea of solving this was (6-y)/6, as in (number of values left)/total space. This failed on a few test cases and I'm pretty sure z and x have to play a part in the equation somehow.
I'm not asking for exact answers but directions, I really want to understand this and why my answer is so awe-full, the other variables add restrictions, how do I arrive at an equation that shows this? Thank you so much. Some links to similar questions would also be greatly appreciated!