If f(x)=.ax^2+bx+2 ,x<2
.gx^2+x+4 ,x>=2
find the real numbers a,b,c so that the tangent of Cf at A(2,f(2)) is vertical to the straight line m=x-3y+7 = 0
If f(x)=.ax^2+bx+2 ,x<2
.gx^2+x+4 ,x>=2
find the real numbers a,b,c so that the tangent of Cf at A(2,f(2)) is vertical to the straight line m=x-3y+7 = 0
Last edited by GeorgieB; 02-27-2018 at 05:26 PM.
Does the above mean the following?
. . . . .[tex]f(x)\, =\, \begin{cases}ax^2\, +\, bx\, +\, 2&\mbox{ for }\, x\, <\, 2 \\gx^2\, +\, \hphantom{b}x\, +\, 4&\mbox{ for }\, x\, \geq\, 2\end{cases}[/tex]
Is the "g" supposed to be a "c"?
What is "Cf"? Does "A(2, f(2))" mean "the point A, which is located at (2, f(2))", or something else? What is the meaning of "m = x - 3y + 7 = 0"? Is this supposed to be "the line 'm', given by x - 3y + 7 = 0", or something else?
What have you tried so far? Where are you getting stuck?
Please be complete. Thank you!
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