Results 1 to 2 of 2

Thread: Help with tangent exercise: If f(x)=.ax^2+bx+2 ,x<2 .gx^2+x+4 ,x>=2, then....

  1. #1

    Help with tangent exercise: If f(x)=.ax^2+bx+2 ,x<2 .gx^2+x+4 ,x>=2, then....

    If f(x)=.ax^2+bx+2 ,x<2
    .gx^2+x+4 ,x>=2

    find the real numbers a,b,c so that the tangent of Cf at A(2,f(2)) is vertical to the straight line m=x-3y+7 = 0
    Last edited by GeorgieB; 02-27-2018 at 05:26 PM.

  2. #2
    Elite Member stapel's Avatar
    Join Date
    Feb 2004
    Posts
    15,887

    Cool

    Quote Originally Posted by GeorgieB View Post
    If f(x)=.ax^2+bx+2 ,x<2
    .gx^2+x+4 ,x>=2
    Does the above mean the following?

    . . . . .[tex]f(x)\, =\, \begin{cases}ax^2\, +\, bx\, +\, 2&\mbox{ for }\, x\, <\, 2 \\gx^2\, +\, \hphantom{b}x\, +\, 4&\mbox{ for }\, x\, \geq\, 2\end{cases}[/tex]

    Is the "g" supposed to be a "c"?

    Quote Originally Posted by GeorgieB View Post
    find the real numbers a,b,c so that the tangent of Cf at A(2,f(2)) is vertical to the straight line m=x-3y+7 = 0
    What is "Cf"? Does "A(2, f(2))" mean "the point A, which is located at (2, f(2))", or something else? What is the meaning of "m = x - 3y + 7 = 0"? Is this supposed to be "the line 'm', given by x - 3y + 7 = 0", or something else?

    What have you tried so far? Where are you getting stuck?

    Please be complete. Thank you!

Bookmarks

Posting Permissions

  • You may not post new threads
  • You may not post replies
  • You may not post attachments
  • You may not edit your posts
  •