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Thread: Help me solve (1-2x)/(2x+1) + (x^2+3x)/(4x^2-1) [div] (3+x)/(4x+2)

  1. #1

    Exclamation Help me solve (1-2x)/(2x+1) + (x^2+3x)/(4x^2-1) [div] (3+x)/(4x+2)

    Please help me solve this equation for x:

    . . . . .[tex]\dfrac{1\, -\, 2x}{2x\, +\, 1}\, +\, \dfrac{x^2\, +\, 3x}{4x^2\, -\, 1}\, \div\, \dfrac{3\, +\, x}{4x\, +\, 2}[/tex]

    Thanks so much.
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    Last edited by stapel; 03-03-2018 at 08:54 PM. Reason: Typing out the text in the graphic; creating useful subject line.

  2. #2
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    Quote Originally Posted by leap2004 View Post
    Please help me solve this equation for x:

    . . . . .[tex]\dfrac{1\, -\, 2x}{2x\, +\, 1}\, +\, \dfrac{x^2\, +\, 3x}{4x^2\, -\, 1}\, \div\, \dfrac{3\, +\, x}{4x\, +\, 2}[/tex]

    Thanks so much.
    1) Not an equation. Click that link you accidentally created (inside your post) and read more on that.

    2) The general idea on such a ponderous expression is to factor every piece of it, try to rewrite it in a useful fashion, and see what factors you can eliminate.

    Let's see where you go with it.
    Last edited by stapel; 03-03-2018 at 08:56 PM. Reason: Copying typed-out graphical content into reply.
    "Unique Answers Don't Care How You Find Them." - Many may have said it, but I hear it most from me.

  3. #3
    Elite Member stapel's Avatar
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    Cool

    Quote Originally Posted by leap2004 View Post
    Please help me solve this equation for x:

    . . . . .[tex]\dfrac{1\, -\, 2x}{2x\, +\, 1}\, +\, \dfrac{x^2\, +\, 3x}{4x^2\, -\, 1}\, \div\, \dfrac{3\, +\, x}{4x\, +\, 2}[/tex]
    We'll be glad to help you "simplify" this "expression"! But we'll first need to see where you're having trouble. So please reply with a clear listing of your thoughts and efforts so far, starting with the flipping of the one fraction to convert the division to multiplication, and then showing your factorisations. Thank you!

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