Hi All,

I'm trying to solve for V52 in this equation AJ52=AJ12+V52*(1-Y52)*AA52+(1-AG52)*(AD12+V52*(1-Y52)*(1-AA52))

I was able to get 1 of the V52 to one side of the equation but this part:
(1-AG52)*(AD12+V52*(1-Y52)*(1-AA52) I can't separate this V52 out of here

Any help would be very very very much appreciated.

2. Originally Posted by tryingtoexcelatmath
Hi All,

I'm trying to solve for V52 in this equation AJ52=AJ12+V52*(1-Y52)*AA52+(1-AG52)*(AD12+V52*(1-Y52)*(1-AA52))

I was able to get 1 of the V52 to one side of the equation but this part:
(1-AG52)*(AD12+V52*(1-Y52)*(1-AA52) I can't separate this V52 out of here

Any help would be very very very much appreciated.

Please share your work with us ...even if you know it is wrong.

If you are stuck at the beginning tell us and we'll start with the definitions.

http://www.freemathhelp.com/forum/announcement.php?f=33

3. Hi Guys,

This was my thought process..

a = b + c*(1 - d)*e + (1 - f)*[g + c*(1 - d)*(1 - e)]

a - b =
c*(1 - d)*e + (1 - f)*[g + c*(1 - d)*(1 - e)]

a - b -
(1 - f)*[g + c*(1 - d)*(1 - e)] = c*(1 - d)*e

a - b - (1 - f)*[g + c*(1 - d)*(1 - e)] / (1 - d)*e = c

But then I have the other C that I haven't been able to get out

Am I suppose to do PEMDAS backwards? I think there must be some simplifying rules that I am forgetting.

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