Is an angle equal to the lenght of one side of triangle where the altitude is situate

Prince

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Is there a difference of unit between dimensionless measure of angles and length in triangles? For example two sides are composed of a distance of \(\displaystyle 0.85cm+0.4cm=1.25cm\) and at the same time \(\displaystyle 0.4cm=\cos\theta\) , where the altitude is situated on one of side of the triangle, and the base is \(\displaystyle 1cm\)?

For consecutive number or non consecutive numbers \(\displaystyle x<y<z\) I have the following answer:

\(\displaystyle (((\frac{\sqrt\frac{y}{z}}{(1-\frac{x}{z})\times\sqrt\frac{x+z}{z-x}})\times\frac{x}{z})+\sqrt\frac{z-y}{z})\times((1-\frac{x}{z})\times\sqrt\frac{(x+z)}{(z-x)})=\sin A\)

\(\displaystyle (\frac{\sqrt\frac{y}{z}}{(1-\frac{x}{z})\times\sqrt\frac{x+z}{z-x}})-(((\frac{\sqrt\frac{y}{z}}{(1-\frac{x}{z})\times\sqrt\frac{x+z}{z-x}})\times\frac{x}{z})+\sqrt\frac{z-y}{z})\times(\frac{x}{z})=\cos A\)

\(\displaystyle \sqrt\frac{(z-y)}{z}=\cos B\)

\(\displaystyle \sqrt\frac{y}{z}=\sin B\)

\(\displaystyle \frac{x}{z}=\cos C\)

\(\displaystyle ((1-\frac{x}{z})\times\sqrt\frac{(z+x)}{(z-x)})=\sin C\)

\(\displaystyle (\sqrt{\frac{y}{z}}\times\frac{x}{z})+\sqrt\frac{z-y}{z}\times((1-\frac{x}{z})\times\sqrt\frac{(z+x)}{(z-x)})=\sin A\)

\(\displaystyle (-\sqrt{\frac{z-y}{z}})\times\frac{x}{z}+\sqrt{\frac{y}{z}}\times((1-\frac{x}{z})\times\sqrt\frac{(z+x)}{(z-x)})=\cos A\)

The following variables \(\displaystyle a,b,c\) represent the length of the sides of the triangles.The angles have no unit but the lengths do.

\(\displaystyle \frac{\sin A}{\sin C}=a\)

\(\displaystyle \frac{\sin B}{\sin C}=b\)

$\frac{\sin C}{\sin C}=c[/tex]

h=altitude

\(\displaystyle \frac{h_c}{h_a}=a\)

\(\displaystyle \frac{h_c}{h_b}=b\)

\(\displaystyle \frac{h_c}{h_c}=c\)


\(\displaystyle ((((\frac{\sin B}{\sin C})\times\cos C)+\cos B)\times\sin C)=\sin A\)

\(\displaystyle (\frac{\sin B}{\sin C})-((((\frac{\sin B}{\sin C})\times\cos C)+\cos B)\times\cos C)=\cos A\)

\(\displaystyle ((((\frac{\sin A}{\sin C})\times\cos C)+\cos A)\times\sin C)=\sin B\)

\(\displaystyle (\frac{\sin A}{\sin C})-((((\frac{\sin A}{\sin C})\times\cos C)+\cos A)\times\cos C)=\cos B\)


And you can obtain all six theta of trigonometric functions \(\displaystyle \sin\theta\) and \(\displaystyle \cos\theta\) with consecutive or non consecutive numbers, where \(\displaystyle x<y<z\)
 
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Is there a difference of unit between dimensionless measure of angles and length in triangles? For example two sides are composed of a distance of \(\displaystyle 0.85cm+0.4cm=1.25cm\) and at the same time \(\displaystyle 0.4cm=\cos\theta\) , where the altitude is situated on one of side of the triangle, and the base is \(\displaystyle 1cm\)?
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And you can obtain all six theta of trigonometric functions \(\displaystyle \sin\theta\) and \(\displaystyle \cos\theta\) with consecutive or non consecutive numbers, where \(\displaystyle x<y<z\)

I have no idea what your work means, or how it is related to the question. But the answer to the question is that an angle can never be equal to a length, because they are different kinds of quantities. Furthermore, a cosine can't have units (it must be a dimensionless ratio).

And "all six theta" is meaningless; "all six trig functions of theta" would mean something.
 
I have a triangle \(\displaystyle \angle\ABC \)from A to B the lenght is 1cm(the base)and from B to C equal \(\displaystyle 1.25cm\) and \(\displaystyle 1.25cm=0.85cm+0.4cm\).Between 0.85cm and 0.4cm, the leg of the altitude is found. Therefore \(\displaystyle 0.5cm÷1.25cm=0.4\theta\) and 0.4cm which matches \(\displaystyle 0.4 theta.\)
 
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I have a triangle \(\displaystyle \angle ABC \)from A to B the lenght is 1cm(the base)and from B to C equal \(\displaystyle 1.25cm\) and \(\displaystyle 1.25cm=0.85cm+0.4cm\).Between 0.85cm and 0.4cm, the leg of the altitude is found. Therefore \(\displaystyle 0.5cm÷1.25cm=0.4\theta\) and 0.4cm which matches \(\displaystyle 0.4 theta.\)

I don't understand any of this, either. Please upload a picture of this triangle, or else explain it so that anyone can draw it. Are there any right angles? What is it that is 0.85, 0.4, etc. centimeters long? What is "the leg of the altitude"? And where is theta?
 
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