ManolitoAguirre
New member
- Joined
- May 15, 2018
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What is the slope of the function y = x2 at x = 3 ?
At x = 3, y = 32 = 9
At x = (3 + Δx), y = (3 + Δx)2 = 9 + 6Δx + (Δx)2
The difference between the y values from x = 3 to x = (3 + Δx)
= 9 + 6Δx + (Δx)2* − 9
= 6Δx + (Δx)2*
Now we can calculate the slope:
As Δx shrinks towards zero we are left with:
Slope = 6
I did this question on Mathopolis. Question is: in the middle of the equation, did the 6 come from adding 3 and 3?
Thank you for your help!
Sent from my SM-T560NU using Tapatalk
At x = 3, y = 32 = 9
At x = (3 + Δx), y = (3 + Δx)2 = 9 + 6Δx + (Δx)2
The difference between the y values from x = 3 to x = (3 + Δx)
= 9 + 6Δx + (Δx)2* − 9
= 6Δx + (Δx)2*
Now we can calculate the slope:
As Δx shrinks towards zero we are left with:
Slope = 6
I did this question on Mathopolis. Question is: in the middle of the equation, did the 6 come from adding 3 and 3?
Thank you for your help!
Sent from my SM-T560NU using Tapatalk