Find perimeter and area: right triangle w/ 2 legs equal; hypot. is 62

[happiness]

I need help with number 5.

Sent from my LGMS210 using Tapatalk

 

[HallsofIvy]

Pretty straightforward. This is a right triangle so you can apply the Pythagorean theorem. The two legs have length x and the hypotenuse has length 62 cm. \(\displaystyle x^2+ x^2= 2x^2= (62)^2= 3844\). Once you have x, it is easy to find the perimeter and area.

 

[happiness]

Pretty straightforward. This is a right triangle so you can apply the Pythagorean theorem. The two legs have length x and the hypotenuse has length 62 cm. \(\displaystyle x^2+ x^2= 2x^2= (62)^2= 3844\). Once you have x, it is easy to find the perimeter and area.

I thank you for your help.

Sent from my LGMS210 using Tapatalk