Sigma Q: sum[k=1,4]5k^2 (don't understand their solution ?)

ManolitoAguirre

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Q. What is the value of \(\displaystyle \displaystyle \sum_{k=1}^4\, 5k^2\,\)?



I guessed the answer, but I was wondering about their solution:



A. Use the formula

. . .\(\displaystyle \displaystyle \sum_{k=1}^n\, k^2\, =\, \dfrac{1}{6}\, n\, (n\, +\, 1)\, (2n\, +\, 1)\)

Therefore

. . .\(\displaystyle \displaystyle \sum_{k=1}^4\, 5k^2\, =\, 5\, \sum_{k=1}^4\, k^2\)

. . . . .\(\displaystyle \displaystyle =\, 5\,\times\, \dfrac{1}{6}\, \times\, 4\, \times\, 5\, \times\, 9\, =\, 150\)



In the question, where did 1/6 come from?

Thank you ;)

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Last edited by a moderator:
Q. What is the value of \(\displaystyle \displaystyle \sum_{k=1}^4\, 5k^2\,\)?



I guessed the answer, but I was wondering about their solution:



A. Use the formula

. . .\(\displaystyle \displaystyle \sum_{k=1}^n\, k^2\, =\, \dfrac{1}{6}\, n\, (n\, +\, 1)\, (2n\, +\, 1)\)

Therefore

. . .\(\displaystyle \displaystyle \sum_{k=1}^4\, 5k^2\, =\, 5\, \sum_{k=1}^4\, k^2\)

. . . . .\(\displaystyle \displaystyle =\, 5\,\times\, \dfrac{1}{6}\, \times\, 4\, \times\, 5\, \times\, 9\, =\, 150\)



In the question, where did 1/6 come from?

Thank you ;)

From knowing a-priori:

1 + 22 + 32 + 42.....+ (n-1)2 + n2 = 1/6 * n * (n+1) * (2n+1)

Do a google-search on "sum of square series" for detailed method.
 
Last edited by a moderator:
Q. What is the value of \(\displaystyle \displaystyle \sum_{k=1}^4\, 5k^2\,\)?



I guessed the answer, but I was wondering about their solution:



A. Use the formula

. . .\(\displaystyle \displaystyle \sum_{k=1}^n\, k^2\, =\, \dfrac{1}{6}\, n\, (n\, +\, 1)\, (2n\, +\, 1)\)

Therefore

. . .\(\displaystyle \displaystyle \sum_{k=1}^4\, 5k^2\, =\, 5\, \sum_{k=1}^4\, k^2\)

. . . . .\(\displaystyle \displaystyle =\, 5\,\times\, \dfrac{1}{6}\, \times\, 4\, \times\, 5\, \times\, 9\, =\, 150\)



In the question, where did 1/6 come from?
It's just part of the formula they gave you. Either they proved the formula (maybe in the section on induction proofs), or they just gave it to you to use (and perhaps memorize for the next test). ;)
 
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