Question: ABCDE.......is a regular polygon with n sides. Write an expression for the size of angle ACD in terms of n.
So I drew this:
This means the angle at C can be worked out as the interior angle minus one of the base angles of the isosceles triangle formed by the line AC. So the formula for the interior angle is: (n-2)180/n and the base angle will be 0.5[180-(n-2)180/n]
So I put that together to get: ACD = (n-2)180/n - 0.5[180 -(n-2)180/n] am I on the write track here? And can anyone help me simplify this cumbersome expression?
Many thanks, as always for generous help.
So I drew this:
This means the angle at C can be worked out as the interior angle minus one of the base angles of the isosceles triangle formed by the line AC. So the formula for the interior angle is: (n-2)180/n and the base angle will be 0.5[180-(n-2)180/n]
So I put that together to get: ACD = (n-2)180/n - 0.5[180 -(n-2)180/n] am I on the write track here? And can anyone help me simplify this cumbersome expression?
Many thanks, as always for generous help.