Polar Equation conversion from r=2-cos(theta) to rectangular

tberri13

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May 25, 2018
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Hi! So, I've been struggle with converting polar equations to rectangular form and this is the problem I need help with: r=2-cos(theta). We were given the correct answer: 0=(x^4)+(2x^3)-(3x^2)+(2x^2)(y^2)+(xy)-(4y^2)+(y^4), but I have no idea how to get there. Any help/suggestions would be greatly appreciated. Thanks!
This is how far I got, but I don't even know if I started the problem correctly so...
math help small.JPG
 
Hi! So, I've been struggle with converting polar equations to rectangular form and this is the problem I need help with: r=2-cos(theta). We were given the correct answer: 0=(x^4)+(2x^3)-(3x^2)+(2x^2)(y^2)+(xy)-(4y^2)+(y^4), but I have no idea how to get there. Any help/suggestions would be greatly appreciated. Thanks!
This is how far I got, but I don't even know if I started the problem correctly so...
View attachment 9535

You almost had it!!

x^2 + y^2 = 2R - Rcos(Θ)

x^2 + y^2 = 2R - x

[x^2 + y^2 + x] = 2R ....... square again

[x^2 + y^2 + x]^2 = 4(x^2 + y^2)

simplify......
 
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