What have you tried? Where are you stuck? What is preventing a parallelogram from being a trapezoid?How can I change the angles of parallelogram to become trapezoid?
What is preventing a parallelogram from being a trapezoid?What have you tried? Where are you stuck? What is preventing a parallelogram from being a trapezoid?
Please show us some work so we know what you need help with.
That is not true!!! A trapezoid is a four sided figure that does have one pair of opposite sides parallel. In fact, the definition does NOT say that both pairs of opposite sides can't be parallel. Hence all parallelogram are trapezoids.What is preventing a parallelogram from being a trapezoid?
The trapoezoid have two pair of non-parallel sides that are parallel in the parallelogram !!!
A quadrilateral has only two distinct angles, so no need to have alpha, beta, gamma and delta. In fact just knowing alpha is enough to know the four angles (given alpha, beta = 180 - alpha).I have a quadriletal that is a parralogram with angle alpha, beta, gamma and delta.
I have a trapozoid with angle alpha2, beta2, etc.
sin(alpha) = cos(alpha2)
What is values alpha can be?
I have a quadriletal that is a parralogram with angle alpha, beta, gamma and delta.
I have a trapozoid with angle alpha2, beta2, etc.
sin(alpha) = cos(alpha2)
What is values alpha can be?
That is not true!!! A trapezoid is a four sided figure that does have one pair of opposite sides parallel. In fact, the definition does NOT say that both pairs of opposite sides can't be parallel. Hence all parallelogram are trapezoids.
A quadrilateral having two and only two sides parallel is called a trapezoid.The Trapezoid of my definition
https://sites.math.washington.edu/~king/coursedir/m444a00/syl/class/trapezoids/Trapezoids.html
I have = given. Or both (the paralleogram and trapezoid) are given.I think we need more information. Could you show us a picture of what you are doing?
When you say "I have ...", do you mean both are given? Or, as your title implies, are you given the parallelogram and want to make a trapezoid with the indicated relationship? Or, as your question here suggests, is it the trapezoid that is known?
Can you see how the angles alpha and alpha2 will be related? Once you have found alpha2, one other angle will be known, but the rest of the trapezoid is free -- you can't determine all sides and angles from only what you have told us. So there must be more to the problem.
It is very important that you tell helpers the entire problem.
I have = given. Or both (the paralleogram and trapezoid) are given.
(1) I don't understand. Why I need two angle that are given?
(2) Can the other angle be calculate by 180-anglevalue?
(3) What the diffuclity with what I ask? - I read your reply and I don't understand.
Can one give me in list of detail why it is impossible to answer the question?
The solution can be written in computer language.
I need a clue.Who said it was impossible to answer the question? That is very simple, if we take it as stated; as I said, you came close.
alpha = ___ - alpha2 or alpha = ___ + alpha2.
As we ask in https://www.freemathhelp.com/forum/threads/41537-Read-Before-Posting!!, please "Post the complete text of the exercise".
The instruction of writting in computer language was not mention in the page of the question but in the end of the text of the work.
But the near the title was written read all the text before answering. (My mistake that I don't follow it ())
I don't know what is in the blank.
I know only that there is supplement angles as you said. But, I guess maybe 180. But I don't know (!!).
A quadrilateral has only two distinct angles, so no need to have alpha, beta, gamma and delta.
In fact just knowing alpha is enough to know the four angles (given alpha, beta = 180 - alpha).
How can I change the angles of parallelogram to become trapezoid?
A quadrilateral has only two distinct angles, so no need to have alpha, beta, gamma and delta. In fact just knowing alpha is enough to know the four angles (given alpha, beta = 180 - alpha).
I don't know how you are making this claim.
Picture convex Quadrilateral ABCD on the xy-axes. Let point C be at the origin and let angle C have a measure of 75 degrees.
Let point D be to the right of point C and also on the x-axis, and let angle D have a measure of 60 degrees. Let side CD be
the longest side of the quadrilateral. (Extend it as needed.)
Here's another interpretation, using complimentary angles.It is an experment … I have a quadriletal that is a parralogram with angle alpha …
I have a trapozoid with angle alpha2 …
sin(alpha) = cos(alpha2)
What is values alpha can be?
I meant parallelogram, not quadrilateralI don't know how you are making this claim.
Picture convex Quadrilateral ABCD on the xy-axes. Let point C be at the origin and let angle C have a measure of 75 degrees.
Let point D be to the right of point C and also on the x-axis, and let angle D have a measure of 60 degrees. Let side CD be
the longest side of the quadrilateral. (Extend it as needed.)
Let points A and B be in Quadrant I. Let the measure of angle B be 90 degrees and the measure of angle A be 135 degrees.
The sum of the four interior angles is 360 degrees (necessarily for a quadrilateral).
Imagine building the quadrilateral up from the x-axis from scratch. You have the side CD. The sizes of angles C and D are
independent of each other. Side BC is a side of the angle C, and side AD is a side of the angle D. Those two side lengths are not
set. Therefore, the measures of angles A and B can vary.
What I see supported in this context is: "If you know the measures of three unique interior angles of a general quadrilateral,
then the measure of the fourth interior angle is determined. ** However, if you know the measures of exactly two unique interior
angles of a general quadrilateral, then the measures of the two remaining interior angles will not necessarily be able to be
determined."
** . . . For example, m<B = 360 degrees - (m<C + m<D + m<A)