Phatfoo
New member
- Joined
- May 22, 2018
- Messages
- 16
First of all, there are no equations here.
You need to come up with two functions that squeeze the given function and have the same limit. This would prove that the given function has the same limit.
Also use the fact that e^x is always ≥ 0 → sin(e^x)>0 → [3-sin(e^x)]≤3
because e^x ≥ 0 → sin(e^x) ~ sin(1) > 0Why is sin(e^x)>0? If x is close to 0?