Finding Vector A having same direction as <-6,7,6> but a length of 3

Christian.

New member
Joined
Sep 1, 2018
Messages
19
Good afternoon everyone,
I am either solving this problem with the wrong technique or I am making a mistake somewhere. The online homework will not take my answer.

Problem:
Find a vector “A” that has the same direction as <-6,7,6> but a length of 3.

How I solved it:
3(<-6,7,6>)
Vector “A”= <-18, 21,18>
 
Instead of multiplying the given vector by 3, you want to multiply by:

\(\displaystyle \dfrac{3}{\sqrt{(-6)^2+7^2+6^2}}=\,?\)
 
Good afternoon everyone,
I am either solving this problem with the wrong technique or I am making a mistake somewhere. The online homework will not take my answer.

Problem:
Find a vector “A” that has the same direction as <-6,7,6> but a length of 3.

How I solved it:
3(<-6,7,6>)
Vector “A”= <-18, 21,18>
No, that has 3 times the length of <-6, 7, 6>

Instead:
1) Find the length of <-6, 7, 6>
2) Divide <-6, 7, 6> by that length to get a vector in the same direction with length 1.
3) Multiply that new vector by 3 to get a vector in the same direction with length 3.

You can do both (2) and (3) at once by multiplying <-6, 7, 6> by 3/length.
 
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