[FONT="]the problem is: dy/dt=2y+1[/FONT]
[FONT="]
[/FONT]
[FONT="]I got y=1/2(e2(t+c) -1) while the book solution is y=ke2t-1/2. Would my solution be acceptable? I also have to solve the ivp for this problem which is y(0)=3. Using my first solution I first did:[/FONT]
[FONT="]3=1/2(eo *e2c)-1[/FONT]
[FONT="]4=1/2(e2c)[/FONT]
[FONT="]8=e2c[/FONT]
[FONT="]How do I solve for c or did I do this wrong?[/FONT]
[FONT="]
[/FONT]
[FONT="]I got y=1/2(e2(t+c) -1) while the book solution is y=ke2t-1/2. Would my solution be acceptable? I also have to solve the ivp for this problem which is y(0)=3. Using my first solution I first did:[/FONT]
[FONT="]3=1/2(eo *e2c)-1[/FONT]
[FONT="]4=1/2(e2c)[/FONT]
[FONT="]8=e2c[/FONT]
[FONT="]How do I solve for c or did I do this wrong?[/FONT]