I think I may be overthinking this problem:
If there are 10 people, and 3 are randomly chosen, what is the probability that person A will be chosen and person B will not be chosen?
My confusion is if person A is the first, second, or third person chosen, how do I account for those different probabilities? At first person A's probability would be 1/10, then 1/9, then 1/8. I'm not sure how to account for this mathematically speaking, and how to account for person B not getting chosen.
If there are 10 people, and 3 are randomly chosen, what is the probability that person A will be chosen and person B will not be chosen?
My confusion is if person A is the first, second, or third person chosen, how do I account for those different probabilities? At first person A's probability would be 1/10, then 1/9, then 1/8. I'm not sure how to account for this mathematically speaking, and how to account for person B not getting chosen.