Finding the rank of a Matric: ( 1 n n ... n ( n 2 n ... n ( n 3 n ... n (............

Xpertery

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Like the title says, find the rank of a Matric

( 1 n n ... n
( n 2 n ... n
( n 3 n ... n
(...............
( n n n ... n )


looks kinda weird, i know, but i don't know how to put horizontal and diagonal dots
Thanks
 
Finding the rank of a Matric

Please help solve the rank of the Matric below



1nn...n
n2n...n
nn3...n
...............
nnn...n
 
It'd have to be an nxn matrix, wouldn't it?

Edit. That's the dimensions not the rank
 
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Consider the cases where n=2, then n=3, then n=4. Can you generalise or see a pattern that might help you prove the general case?
 
it doesn't really say anything about the dimension of the matric.
i did try to consider when n=1 n=2 n=3 n=4 and etc. but i couldn't really put it in a way i can solve.
any help? T.T
Thanks for the reply
 
If nothing else, when looking at cases n= 1, 2, 3, 4, you should have seen that no row is linear combination of other rows.
 
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