jacknowlin
New member
- Joined
- Sep 24, 2018
- Messages
- 2
Hi,
The question asks:
Given ax+by = 1, find the equation of the line which has twice the x-intercept and twice the slope. Write your answer in the form of Px+Qy = 1.
I first changed the first equation to 2ax + by = 1 because of the "twice the x intercept"
Then i put the equation into slope intercept: by=-2ax +1
then doubled the slope: by = -4ax +1
Then wrote the answer in the asked form: 4Px+Qy = 1
I feel like I definitely did this problem wrong because it doesn't really make any sense to me since the first equation is a given, so I feel like doubling the slope to 2ax+by≠1 and the problem wouldn't work.
How else should I approach this problem?
The question asks:
Given ax+by = 1, find the equation of the line which has twice the x-intercept and twice the slope. Write your answer in the form of Px+Qy = 1.
I first changed the first equation to 2ax + by = 1 because of the "twice the x intercept"
Then i put the equation into slope intercept: by=-2ax +1
then doubled the slope: by = -4ax +1
Then wrote the answer in the asked form: 4Px+Qy = 1
I feel like I definitely did this problem wrong because it doesn't really make any sense to me since the first equation is a given, so I feel like doubling the slope to 2ax+by≠1 and the problem wouldn't work.
How else should I approach this problem?