Find root of e^x + x = 3 - x in interval [0, 1] using Newton-Raphson method

lalaland63

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Help Needed! Urgent Do not know how to solve :(

Let \(\displaystyle f(x)\, =\, e^x\, +\, x\) and \(\displaystyle g(x)\, =\, 3\, -\, x.\)

Given that the equation \(\displaystyle g(x)\, =\, f(x)\) has a solution in the interval \(\displaystyle \left[0,\, 1\right],\) use the Newton-Raphson Method to find a root of the equation \(\displaystyle g(x)\, =\, f(x)\) in the interval \(\displaystyle \left[0,\, 1\right],\) to an accuracy of 5 decimal places.


How do I solve this?
 
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Help needed!

Let f(x) =e^x + x and g(x) = 3-x.


Given that the equation g(x) = f(x) has a solution in the interval [0,1] , use the Newton-Raphson Method to find a root of the equation g(x) = f(x) in the interval [0, 1] [ 0 , 1 ] to an accuracy of 5 decimal places.
 
Help Needed! Urgent Do not know how to solve :(

Let \(\displaystyle f(x)\, =\, e^x\, +\, x\) and \(\displaystyle g(x)\, =\, 3\, -\, x.\)

Given that the equation \(\displaystyle g(x)\, =\, f(x)\) has a solution in the interval \(\displaystyle \left[0,\, 1\right],\) use the Newton-Raphson Method to find a root of the equation \(\displaystyle g(x)\, =\, f(x)\) in the interval \(\displaystyle \left[0,\, 1\right],\) to an accuracy of 5 decimal places.


How do I solve this?
Do you know Newton-Raphson Method ?
 
Last edited by a moderator:
Let f(x) =e^x + x and g(x) = 3-x.


Given that the equation g(x) = f(x) has a solution in the interval [0,1] , use the Newton-Raphson Method to find a root of the equation g(x) = f(x) in the interval [0, 1] [ 0 , 1 ] to an accuracy of 5 decimal places.

Your problem could be translated to:

Calculate the roots of w(x) = (e^x + x) - (3-x), using the Newton-Raphson Method in the interval [0, 1] [ 0 , 1 ] to an accuracy of 5 decimal places.
 
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