Self-adjoint boundary conditions for f(b)=cf(a), f′(b)=c′f′(a)

warwick

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Jan 27, 2006
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Under what condition on the constants c and c' are the boundary conditions

\(\displaystyle f(b) = cf(a) \)
\(\displaystyle f'(b) = c'f'(a) \)

self-adjoint for the operator \(\displaystyle L(f) = (rf')' + pf \) on [a,b]? Assume that r and p are real.

Boundary conditions are self-adjoint if

\(\displaystyle [r(f'\bar g - f\bar g')]^b_a = 0\)

Using this evaluation and boundary conditions, I end up with

\(\displaystyle f'(a)\bar g [c'r(b)-r(a)] + f(a)\bar g'[r(a) - cr(b)] = 0\)


which implies that \(\displaystyle c' = c = r(a)/r(b) \)


However, the back of the book has \(\displaystyle c \bar c'= r(a)/r(b).\) What am I doing wrong?
 
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