In the attached I can figure from phytagoras, AC = 25/3 and AD = 7/3 considring AB = AC
and and agin from phtagoras BC = 10.
But then I am stuck.
Answer should be 17View attachment 10467
In the attached I can figure from phytagoras, AC = 25/3 and AD = 7/3 considring AB = AC
and and agin from phtagoras BC = 10.
But then I am stuck.
Answer should be 17View attachment 10467
why?the answer can't be 17.
Now you need to use similar triangle theorems.
Let DA= p and AC = h;
Then:
p/8 = (6+p)/x ... and
(h+9)/x = b/8 .... and
See where does those take you along with Pythagoras.
In the attached I can figure from phytagoras, AC = 25/3 and AD = 7/3 considring AB = AC
and and agin from phtagoras BC = 10.
But then I am stuck.
Answer should be 17
Yes .... I did ... looking at the OPs drawing (without thinking through...Are you assuming that ABE is a right angle? It isn't.
why?