How to factorise after I differentiate

[Zamiii]

Hello

When I differentiate (4t^(2/3))/(t^2+1) I get the numerator as 8/3t^(5/3)+8/3t^(-1/3)-8t^(5/3)

How do I factorise this numerator to get 8/3t^(-1/3)(2t^2-1) (if that's correct)

Thanks

 

[Deleted member 4993]

Hello

When I differentiate (4t^(2/3))/(t^2+1) I get the numerator as 8/3t^(5/3)+8/3t^(-1/3)-8t^(5/3)

How do I factorise this numerator to get 8/3t^(-1/3)(2t^2-1) (if that's correct - it is correct)

Thanks

First factor out 8/3*t^(-1/3) - things will start to look much better.