Results 1 to 2 of 2

Thread: Constructible Solutions: how to prove x^3−6x+2√(pi) has no constructible solutions?

Threaded View

Previous Post Previous Post   Next Post Next Post
  1. #1
    New Member
    Join Date
    Dec 2018
    Posts
    1

    Constructible Solutions: how to prove x^3−6x+2√(pi) has no constructible solutions?

    We know that for cubic polynomial, if there is a constructible root, there is a rational root. But how to prove [tex]x^3-6x+2\sqrt{\pi}[/tex] has no constructible solutions? Any help is really appreciated.
    Last edited by Subhotosh Khan; 12-06-2018 at 09:59 AM.

Tags for this Thread

Bookmarks

Posting Permissions

  • You may not post new threads
  • You may not post replies
  • You may not post attachments
  • You may not edit your posts
  •