Good afternoon,
I know that in the long run you can never win at roulette. The casino will always win, even if you are using the Martingale technique (that doubles your bet with every loss).
But I am curious about how big the probability is that:
* when you play 60 times on black
* the roulette ball will fall on red or zero 11 times in a row
My quick calculation says is 2,44% ( = ( 2^(60 - 11) * (1 + (60 - 11)) - ( 60 - 1) - (((60 - 2) - (11 + 1))/2 * ((60 - 2) + (11 + 1))) )/ 2 ^ 60), but I am pretty sure it is not totally correct.
Who can correct me please?
I know that in the long run you can never win at roulette. The casino will always win, even if you are using the Martingale technique (that doubles your bet with every loss).
But I am curious about how big the probability is that:
* when you play 60 times on black
* the roulette ball will fall on red or zero 11 times in a row
My quick calculation says is 2,44% ( = ( 2^(60 - 11) * (1 + (60 - 11)) - ( 60 - 1) - (((60 - 2) - (11 + 1))/2 * ((60 - 2) + (11 + 1))) )/ 2 ^ 60), but I am pretty sure it is not totally correct.
Who can correct me please?