Amazing discovery

D

Denis

Senior Member
Joined
Feb 17, 2004
Messages
1,707
Just discovered that:
if n is a 4 digit number such that the 2 digit number
formed by its 1st 2 digits is 1 greater than the
2 digit number formed by its last 2 digits,
and n is a square, then only one such n exists: 8281

Unfortunately, such a mathshaking discovery
will not bring down the price of groceries :(
 
Denis said:
Just discovered that:
if n is a 4 digit number such that the 2 digit number
formed by its 1st 2 digits is 1 greater than the
2 digit number formed by its last 2 digits,
and n is a square, then only one such n exists: 8281

Unfortunately, such a mathshaking discovery
will not bring down the price of groceries :(
Click to expand...
It is a good thing that such discoveries - although fantastically mathshaking - will not bring down the price of groceries.

Because that might trigger a vicious cycle of hyper-deflation and the whole human society will be destroyed.

As far as I can tell, even the discovery of "E = mc2" did not bring down the price of groceries!!!
 
Denis said:
Just discovered that:
if n is a 4 digit number such that the 2 digit number
formed by its 1st 2 digits is 1 greater than the
2 digit number formed by its last 2 digits,
and n is a square, then only one such n exists: 8281

Unfortunately, such a mathshaking discovery
will not bring down the price of groceries :(
Click to expand...
And the proof is....
 
I have a foolproof method to bring down the cost of groceries. I've been using it for years, and it requires no calculations or other work. :cool:
 
Denis said:
Are you saying that E = mc^2 is more important than my 8281 discovery:confused:
Click to expand...
No....No... bite my tongue...

I just meant those are equivalently grocery-bill-non-helpers.
 
Denis said:
Are you saying that E = mc^2 is more important than my 8281 discovery:confused:
Click to expand...
\(\displaystyle E = mc^2\) is not so important. It's \(\displaystyle E^2 = (pc)^2 + (mc^2)^2\).

Yes, I'm a purist.

-Dan
 
Everyone is afraid of Sir Denis. People need to take their medications on a regular basis. Clearly Denis isn't taking anything. Or at least anything his doctor would approve of.

-Dan
 
topsquark said:
Everyone is afraid of Sir Denis. People need to take their medications on a regular basis. Clearly Denis isn't taking anything. Or at least anything his doctor would approve of.

-Dan
Click to expand...
Now, now. Be nice. Poor Canadians, the sun doesn't shine for six months of the year, and their native cuisine's high point is Red River cereal (except in Nunavut, the cuisine of which it is improper to speak when children may hear).
 
Denis said:
Fasting?
Click to expand...
Not that extreme, but, yeah, just don't eat so much.

In general, North Americans eat WAY too much (not to mention all of the purchased food that ends up wasted.)
 
Jomo said:
Shoplifting is illegal.
Click to expand...
Yes, boys and girls. Shoplifting is bad, okaaay?

On the other hand, "stealing" $1,000 from Bank of America through their Keep-The-Change program (now defunct) was entirely legal; the bank encouraged me to do it! Although, it did tend to upset the checkers at Safeway (and a few customers, waiting in line behind me) when I used four separate debit cards to pay for four smallest mushrooms or four smallest green beans (each rung up separately) because the scales couldn't always detect the weight force of such small objects -- requiring me to start tossing coins onto the scale, from the use-a-penny/give-a-penny jar.

It was also quite challenging to pump one cent worth of gasoline (the quickest squeeze on the handle almost always generated a three-cent charge). However, pumping/paying, pumping/paying, pumping/paying and pumping/paying (with each of the four debit cards) was considerably less stressful for all than with the mushroom and bean episodes, as I simply avoided overheated cashiers by paying at the pump. At least, no one waiting for the pump ever started screaming, like some did inside Safeway …

After three months, I took the banker's $1,000. Was it worth the trouble? You bet it was! We're talkin' Bank of America, here. :twisted:
 
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topsquark said:
\(\displaystyle E = mc^2\) is not so important. It's \(\displaystyle E^2 = (pc)^2 + (mc^2)^2\).

Yes, I'm a purist.

-Dan
Click to expand...
Wait a minute .... since you are purist, that m should have been:

mo = rest mass - we are referring to two different types of masses here....
 
Subhotosh Khan said:
Wait a minute .... since you are purist, that m should have been:

mo = rest mass - we are referring to two different types of masses here....
Click to expand...
Modern convention uses "m" as the only mass of the particle, not just being the rest mass. Any use of reference frames puts the speed dependence in the 4-momentum.

-Dan

Addendum: That's a Particle Physics convention. Now that I think of it I don't know what conventions the Relativists use.
 
JeffM said:
Now, now. Be nice. Poor Canadians, the sun doesn't shine for six months of the year, and their native cuisine's high point is Red River cereal (except in Nunavut, the cuisine of which it is improper to speak when children may hear).
Click to expand...
I'll have you know that we're the world's top producers
of maple syrup and poutine !!
<...and hockey pucks...>
 
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