Many thanks to those who helped me solve my last problem, I would appreciate any suggestions on this last question. I have listed the steps below that I have tried
Any help would be gratefully appreciated
Question from my A level maths text book
Solve this pair of simultaneous equation by eliminating either the terms in x^2 or the terms in Y^2?
X^2 +Y^2 -3X =9 (Eq 1)
X^2 - Y^2 +X + 4Y = 3 (Eq 2)
Adding both together
2X^2 -2X +4Y =12
Second attempts Now I get this
2x^ -2x -12 = -4y
2x^2 -2x -12 /-4 =y
-1/2x^2 - 1/2x -3 =y
Therefor
x^2 +(-1/2x^2 -1/2x -3)^2 -3x = 9
Is this correct so far?
Second attempt
Multiply equation 2 by 3
3X^2 - 3Y^2 +3X +12Y = 9
Eq 1 =Eq 2
3X^2 - 3Y^2 +3X + 12 Y = X^2 +Y^2 -3X
3X^2 - 3Y^2 + 3X +12 Y - X^2 -Y^2 +3X =0
3X^2 - X^2 +6X - 3Y^2 - Y^2 +12Y = 0
2X^2 +6X -4Y^2 +12Y = 0
X^2 + 3X -2Y^2 +6Y = 0
X^2 +3X = 2Y^2 - 6Y
Can not get x or y on its own
I can not get any further, I have tried for many hours, I have solved 17 equations on the page of my text book but I seem to be stuck on the last one
Would appreciate any suggestions
Many thanks in advance
Barry
Any help would be gratefully appreciated
Question from my A level maths text book
Solve this pair of simultaneous equation by eliminating either the terms in x^2 or the terms in Y^2?
X^2 +Y^2 -3X =9 (Eq 1)
X^2 - Y^2 +X + 4Y = 3 (Eq 2)
Adding both together
2X^2 -2X +4Y =12
Second attempts Now I get this
2x^ -2x -12 = -4y
2x^2 -2x -12 /-4 =y
-1/2x^2 - 1/2x -3 =y
Therefor
x^2 +(-1/2x^2 -1/2x -3)^2 -3x = 9
Is this correct so far?
Second attempt
Multiply equation 2 by 3
3X^2 - 3Y^2 +3X +12Y = 9
Eq 1 =Eq 2
3X^2 - 3Y^2 +3X + 12 Y = X^2 +Y^2 -3X
3X^2 - 3Y^2 + 3X +12 Y - X^2 -Y^2 +3X =0
3X^2 - X^2 +6X - 3Y^2 - Y^2 +12Y = 0
2X^2 +6X -4Y^2 +12Y = 0
X^2 + 3X -2Y^2 +6Y = 0
X^2 +3X = 2Y^2 - 6Y
Can not get x or y on its own
I can not get any further, I have tried for many hours, I have solved 17 equations on the page of my text book but I seem to be stuck on the last one
Would appreciate any suggestions
Many thanks in advance
Barry
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