aron101782
New member
- Joined
- Jan 18, 2019
- Messages
- 26
Find the volume of the solid that the cylinder r=acost cuts out of the sphere of radius a.
I am getting two different solutions. When integrating
4I(0 pi/2)I(0 acost)I(0 (a^2-r^2)^(1/2)) r dz dr dt = 1.205
(correct in the solutions manual)
I(-pi/2 pi/2)I(0 acost)I(-(a^2-r^2)^1/2 (a^2-r^2)1/2) r dz dr dt = 2.09
(incorrect in the solutions manual)
if if this is true. I would like to know why it is incorrect to integrate through the entire region. And correct to integrate through the sub region and multiply by 4.
I am getting two different solutions. When integrating
4I(0 pi/2)I(0 acost)I(0 (a^2-r^2)^(1/2)) r dz dr dt = 1.205
(correct in the solutions manual)
I(-pi/2 pi/2)I(0 acost)I(-(a^2-r^2)^1/2 (a^2-r^2)1/2) r dz dr dt = 2.09
(incorrect in the solutions manual)
if if this is true. I would like to know why it is incorrect to integrate through the entire region. And correct to integrate through the sub region and multiply by 4.