3's galore

Denis

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Feb 17, 2004
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1,707
Using exactly ten 3's, get 6313.

Allowed: + - * / ! ^ and brackets : nothing else!
 
Using exactly ten 3's, get 6313.

Allowed: + - * / ! ^ and brackets : nothing else!

Here is a solution:

(I used extra parentheses for emphasis of sections.)

(3^(3!/3))((3^(3!)) - (3^3)) - 3 - (3!/3) = 6313

- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

(3^2)(3^6 - 3^3) - 3 - 2 =

(9)(729 - 27) - 5 =

(9)(702) - 5 =

6318 - 5 =

6313
 
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Nice one Lookagain! Mine's somewhat similar:

3*3*(3!)! - (3+3)*3^3 - 3! + 3/3 = 6313
...9*720...-......6*27.....-6...+...1 = 6313
 
Denis, including yours, this is a third solution:

(3*3!)(3*(3!)!/(3!) - 3*3) - 3! + 3/3 = 6313

________________________________________

(3*6)(3*6!/6 - 9) - 6 + 1 =
(18)(3*720/6 - 9) - 5 =
(18)(2160/6 - 9) - 5 =
(18)(360 - 9) - 5 =
(18)(351) - 5 =
6318 - 5 =
6313
 
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4)

((3!)!/3)(3^3) - (3^3)(3!) - 3 - 3!/3 = 6313

5)

(3^3)((3!)!/3 - 3!) - 3!/3 + 3 - 3 - 3 = 6313

6)

(3^3)(3!)(3^3 + 3! + 3!) - 3 - 3!/3 = 6313

7)

(3^3)(3!)((3!)^(3!/3) + 3) - 3 - 3!/3 = 6313

8)

3*3*3!((3! - 3/3)! - 3) - 3 - 3!/3 = 6313

9)

(3*3*3)((3!)!/3 - 3!) - 3 - (3 + 3)/3 = 6313
 
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