Dr. Peterson, thank you so much for your continued help on this!

To circle back on my original thoughts (geometry pun intended)...

Right now I draw the two boxes in CAD and move/rotate/move/rotate until I can get the the right

angle (theta) & horizontal offset (A_x_offset) combination. It works, and it works quickly, and it works easily... but I thought it would be fun to solve for theta before opening a CAD application (and I thought it was embarrassing that it wasn't obvious to me how I would solve for this)...

But, if I understand correctly, it's not a VERY simple formulaic solution... but instead would use some numerical approximation and/or graphing? Which suddenly makes my move/rotate/move/rotate solution seem less embarrassing.

And from there.... I think all of the rest of my questions can be simplified to:

Rule 1) If B_x_top_in is greater than 0.5 * Bx then it can be cleaned in 2 dips without flipping the longer box upside down.

Rule 2) If "Rule 1" is not true and B_center is "inside" box A then the box can be cleaned in 2 dips but flipping the longer box upside down is required.

Rule 3) As long as B_y < A_y there is no need to dip something more than twice.

I'll think about more generic solutions for general solutions to dipping a box in a box... and maybe share an excel workbook or something.

Thanks again for all the help!

-Mike

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