Salman Ali
New member
- Joined
- Feb 12, 2019
- Messages
- 3
Please find the range of this using inverse function. Because inverse domain is function's range.
I had assumed sloppy wording, in the op (i.e., piecewise functions required).You can't find the range "using inverse function" because \(\displaystyle f(x)=1- 2x- x^2\) doesn't have an inverse function!
Two corrections shown in red. :cool:… complete the square … \(\displaystyle 1 - (x^2 + 2x + 1) + 1 = 1 - (x+ 1)^2\) \(\displaystyle + \; 1\)
… range is from negative infinity to 2.