20% solution added to 50% solution to get 30% solution

bananalanders

New member
Joined
Sep 20, 2006
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2
Hi can anyone help me with this problem, I am having a hard time setting it up. Thanks

How much of a 20% solution of alcohol and how much of a 50% solution should be mixed to give 8 gallons of a 30% solution?
 

skeeter

Senior Member
Joined
Dec 15, 2005
Messages
2,396
let x = number of gallons of 20% solution
then 8 - x = number of gallons of 50% solution

(.20)x + .50(8 - x) = .30(8)

multiply every term by 100 to clear the decimals

20x + 50(8 - x) = 30(8)

solve for x ... then determine 8-x
 

bananalanders

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Sep 20, 2006
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2
thank you so much :D
 
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