B bananalanders New member Joined Sep 20, 2006 Messages 2 Sep 20, 2006 #1 Hi can anyone help me with this problem, I am having a hard time setting it up. Thanks How much of a 20% solution of alcohol and how much of a 50% solution should be mixed to give 8 gallons of a 30% solution?

Hi can anyone help me with this problem, I am having a hard time setting it up. Thanks How much of a 20% solution of alcohol and how much of a 50% solution should be mixed to give 8 gallons of a 30% solution?

skeeter Senior Member Joined Dec 15, 2005 Messages 2,396 Sep 20, 2006 #2 let x = number of gallons of 20% solution then 8 - x = number of gallons of 50% solution (.20)x + .50(8 - x) = .30(8) multiply every term by 100 to clear the decimals 20x + 50(8 - x) = 30(8) solve for x ... then determine 8-x

let x = number of gallons of 20% solution then 8 - x = number of gallons of 50% solution (.20)x + .50(8 - x) = .30(8) multiply every term by 100 to clear the decimals 20x + 50(8 - x) = 30(8) solve for x ... then determine 8-x