2l+2w=60 In Standard Form

CoopAloop

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The problem says the perimeter of a rectangle is 2l+2w=p, and it says the perimeter is 30 inches. So 2l+2w=60, it wants me to write that in standard form, but i am confused.
 
Please post original problem exactly as it appears in your book...
The perimeter P of a rectangle is given by 2l+2w=P, where l is the length of the rectangle and w is the width
If the perimeter of the rectangle is 30 inches, write an equation for the perimeter in standard form.
 
The problem says the perimeter of a rectangle is 2l+2w=p, and it says the perimeter is 30 inches. So 2l+2w=60, it wants me to write that in standard form, but i am confused.

The answer depends on just what you mean by standard form. Without any other statement this is generally considered as the form
ax + by = c
where a, b, and c are constant. If a is not zero, some go further and say a should be 1 so that if you had an equation like
2 x + 4 y = 4,
you would re-write the equation as
x + 2 y = 2.

Now let x equal l and y equal w.

For other standard forms, look at
http://oregonstate.edu/instruct/mth251/cq/FieldGuide/linear/lesson.html
 
Boy oh boy...the perimeter of a rectangle = 2(L + W).
Over and out.

Was that really the question? You are given the perimeter value so you have
2L + 2W = 30
or
2 (L+W) = 30
or
L + W = 15
or
...
Which is the standard form?

BTW: For the original po9ster; do you have the answer now? If so, what was it?
 
Last edited:
Was that really the question? You are given the perimeter value so you have
2L + 2W = 30
or
2 (L+W) = 30
or
L + W = 15
or
...
Which is the standard form?

BTW: For the original po9ster; do you have the answer now? If so, what was it?
The answer was x+2y=12
and thank you all for the help
 
Is this a joke? There was no "x" or "y" at all in your original post! That makes no sense as an answer to your original post.
 
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