2t + 8 = 5 _____ 6 12t + 48 = 30 12t = 30- 48 12t = -12 t = -1
G Georgie New member Joined Jul 24, 2006 Messages 2 Aug 7, 2006 #1 2t + 8 = 5 _____ 6 12t + 48 = 30 12t = 30- 48 12t = -12 t = -1
M Mrspi Senior Member Joined Dec 17, 2005 Messages 2,128 Aug 7, 2006 #2 Georgie said: 2t + 8 = 5 _____ 6 12t + 48 = 30 12t = 30- 48 12t = -12 t = -1 Click to expand... You could check this yourself, Georgie. Substitute -1 for "t" in the original equation: [ 2(-1) + 8 ] / 6 = 5 [-2 + 8 ] / 6 = 5 6 / 6 = 5 1 = 5 <-----------NOT TRUE. So, you know your solution is incorrect. It appears that you tried to multiply both sides of the original equation by 6 to get rid of the fraction: 6 * [(2t + 8) / 6] = 6*5 On the left side, multiplying by 6 "undoes" the division by 6, and you will be left with 2t + 8 = 30 Now, subtract 8 from both sides: 2t + 8 - 8 = 30 - 8 2t = 22 Divide both sides by 2: (2t) / 2 = 22 / 2 t = 11 Check. Substitute 11 for t in the original equation: [ 2(11) + 8 ] / 6 = 5 [22 + 8 ] / 6 = 5 30 / 6 = 5 5 = 5 <-------True! It checks. I hope this helps you.
Georgie said: 2t + 8 = 5 _____ 6 12t + 48 = 30 12t = 30- 48 12t = -12 t = -1 Click to expand... You could check this yourself, Georgie. Substitute -1 for "t" in the original equation: [ 2(-1) + 8 ] / 6 = 5 [-2 + 8 ] / 6 = 5 6 / 6 = 5 1 = 5 <-----------NOT TRUE. So, you know your solution is incorrect. It appears that you tried to multiply both sides of the original equation by 6 to get rid of the fraction: 6 * [(2t + 8) / 6] = 6*5 On the left side, multiplying by 6 "undoes" the division by 6, and you will be left with 2t + 8 = 30 Now, subtract 8 from both sides: 2t + 8 - 8 = 30 - 8 2t = 22 Divide both sides by 2: (2t) / 2 = 22 / 2 t = 11 Check. Substitute 11 for t in the original equation: [ 2(11) + 8 ] / 6 = 5 [22 + 8 ] / 6 = 5 30 / 6 = 5 5 = 5 <-------True! It checks. I hope this helps you.
