3−1×(8−2×3) = 3 ⋅ 3 − 1 ⋅ 8

oldtryingtorenew

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How can this equation be true? i cant understand how they rewrote 3−1×(8−2×3) to be 3 ⋅ 3 − 1 ⋅ 8. Can someone explain?
 

Steven G

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Dec 30, 2014
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3−1×(8−2×3)= 3-(8-6) = 3 - 2 =1
3 ⋅ 3 − 1 ⋅ 8 = 9 - 8 = 1
They did say that you can go from 3−1×(8−2×3) to 3 ⋅ 3 − 1 ⋅ 8. They just said that they are equal.

It similar to saying that 5 + 25 = 15*2. Both sides equal 30, but in computing 5+25 you don't get to 15*2!
 
D

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How can this equation be true? i cant understand how they rewrote 3−1×(8−2×3) to be 3 ⋅ 3 − 1 ⋅ 8. Can someone explain?
If you evaluate the Left-Hand-Side and the Right-Hand-Side, you find that "those" collapse to same value (what is it?).

Can you post the complete problem (as it was assigned to you) - verbatim?

That will help us understand the genesis of your query.
 

oldtryingtorenew

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Sep 6, 2022
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im trying to understand how we solve
19x≡4(mod141)

now this i understand
141 = 7 ⋅ 19 + 8
19 = 8 ⋅ 2 + 3
8 = 2 ⋅ 3 + 2
3 = 1 ⋅ 2 + 1
2 = 2 ⋅ 1 + 0

now we
 

JeffM

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Please give the original problem completely and exactly. Your two posts seem to have no relationship to each other.

What are you studying?

You are giving us no information to help us figure out how to help you.
 

Otis

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Apr 22, 2015
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i cant understand how they rewrote [the equation]
3−1×(8−2×3) = 3 ⋅ 3 − 1 ⋅ 8

Hi. I can't understand why they would switch multiplication signs on one side.

When you respond to posts #3 and #7, will you please include the source of the exercise/example text, as well?

Cheers :)
[imath]\;[/imath]
 
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